Subjects algebra

Step 15 Explanation 26F2Ba

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1. We are asked to explain step 15 better. Since the original problem or context is not provided, let's assume step 15 involves simplifying or solving an algebraic expression. 2. Generally, step 15 might involve simplifying a fraction, solving an equation, or factoring an expression. The key is to carefully apply algebraic rules such as distributing, combining like terms, or canceling common factors. 3. For example, if step 15 involves simplifying a fraction like $$\frac{6x}{3}$$, we can divide numerator and denominator by their greatest common divisor 3: $$\frac{\cancel{3} \cdot 2x}{\cancel{3}} = 2x$$ 4. This shows that dividing both numerator and denominator by 3 simplifies the fraction to $$2x$$. 5. If step 15 involves solving an equation, say $$2x + 3 = 7$$, subtract 3 from both sides: $$2x + 3 - 3 = 7 - 3$$ $$2x = 4$$ Then divide both sides by 2: $$\frac{\cancel{2}x}{\cancel{2}} = \frac{4}{2}$$ $$x = 2$$ 6. The key is to perform the same operation on both sides of the equation to maintain equality. If you provide the exact step 15 or the problem, I can give a more precise explanation.