1. **State the problem:** Nick got strikes on $\frac{1}{3}$ of his turns and Brandon got strikes on $\frac{2}{5}$ of his turns. We need to find who got more strikes and by what fraction. 2. **Compare the fractions:** To compare $\frac{1}{3}$ and $\frac{2}{5}$, find a common denominator. 3. **Find common denominator:** The least common denominator of 3 and 5 is 15. 4. **Convert fractions:** $$\frac{1}{3} = \frac{1 \times 5}{3 \times 5} = \frac{5}{15}$$ $$\frac{2}{5} = \frac{2 \times 3}{5 \times 3} = \frac{6}{15}$$ 5. **Compare converted fractions:** $\frac{5}{15}$ (Nick) and $\frac{6}{15}$ (Brandon). Since $\frac{6}{15} > \frac{5}{15}$, Brandon got more strikes. 6. **Find the difference:** $$\frac{6}{15} - \frac{5}{15} = \frac{1}{15}$$ 7. **Conclusion:** Brandon got $\frac{1}{15}$ more strikes than Nick. 8. **Match with options:** Option d states "Brandon got a strike on $\frac{2}{15}$ more of his turns than Nick did," which is incorrect. Option b states "Brandon got a strike on $\frac{1}{15}$ more of his turns than Nick did," which is correct. **Final answer:** Brandon got more strikes by $\frac{1}{15}$.