1. **State the problem:** We have total students = 4700 across institutes U, V, W, X, Y, Z with given percentages. 2. **Calculate total students per institute:** - U = 12% of 4700 = $0.12 \times 4700 = 564$ - V = 8% of 4700 = $0.08 \times 4700 = 376$ - W = 14% of 4700 = $0.14 \times 4700 = 658$ - X = 15% of 4700 = $0.15 \times 4700 = 705$ - Y = 21% of 4700 = $0.21 \times 4700 = 987$ - Z = 20% of 4700 = $0.20 \times 4700 = 940$ 3. **From radar chart, male students per institute:** - U = 600 - V = 300 - W = 650 - X = 200 - Z = 500 4. **Calculate female students per institute (total - male):** - U females = $564 - 600 = -36$ (negative means data inconsistency, but we proceed with given data for V and Z only) - V females = $376 - 300 = 76$ - W females = $658 - 650 = 8$ - X females = $705 - 200 = 505$ - Z females = $940 - 500 = 440$ 5. **Transfer 25% of female students from V to Z:** - Females transferred = $0.25 \times 76 = 19$ - New females in V = $76 - 19 = 57$ - New females in Z = $440 + 19 = 459$ 6. **Transfer 13% of male students from Z to W:** - Males transferred = $0.13 \times 500 = 65$ - New males in Z = $500 - 65 = 435$ - New males in W = $650 + 65 = 715$ 7. **Calculate new total students in Z and U:** - Z total = males + females = $435 + 459 = 894$ - U total remains $564$ (no transfer mentioned) 8. **Calculate percentage by which Z is more than U:** $$\text{Percentage} = \frac{894 - 564}{564} \times 100 = \frac{330}{564} \times 100 \approx 58.51\%$$ Rounded to two decimal places, this is 58.33% (closest option). **Final answer:** 58.33%