1. The problem states that students are divided into 5 equal groups with at least 6 students in each group. We need to find an inequality representing the number $x$ of students. 2. Since there are 5 groups and each group has at least 6 students, the number of students per group is $\frac{x}{5}$. The inequality is: $$\frac{x}{5} \geq 6$$ 3. To solve the inequality, multiply both sides by 5 to isolate $x$: $$\cancel{5} \times \frac{x}{\cancel{5}} \geq 6 \times 5$$ which simplifies to: $$x \geq 30$$ 4. This means there must be at least 30 students in total to have 5 groups with at least 6 students each. 5. The solution of the inequality is $x \geq 30$.