1. **State the problem:** Solve the system of equations by substitution: $$\begin{cases} y + 1 = 2x \\ y = 3x + 2 \end{cases}$$ 2. **Use substitution:** Since $y = 3x + 2$, substitute this into the first equation: $$3x + 2 + 1 = 2x$$ 3. **Simplify the equation:** $$3x + 3 = 2x$$ 4. **Isolate $x$:** $$3x + 3 = 2x$$ $$3x - 2x = -3$$ $$x = -3$$ 5. **Find $y$ by substituting $x$ back into $y = 3x + 2$:** $$y = 3(-3) + 2$$ $$y = -9 + 2$$ $$y = -7$$ 6. **Final solution:** $$(x, y) = (-3, -7)$$ This means the two lines intersect at the point $(-3, -7)$.