1. **State the problem:** Solve the system of equations using substitution: $$4x + 3y = 37$$ $$x = 3y - 2$$ 2. **Substitution method:** Substitute the expression for $x$ from the second equation into the first equation. $$4(3y - 2) + 3y = 37$$ 3. **Expand and simplify:** $$12y - 8 + 3y = 37$$ $$15y - 8 = 37$$ 4. **Isolate $y$:** $$15y = 37 + 8$$ $$15y = 45$$ 5. **Solve for $y$:** $$y = \frac{45}{15}$$ $$y = 3$$ 6. **Substitute $y=3$ back into $x = 3y - 2$ to find $x$:** $$x = 3(3) - 2$$ $$x = 9 - 2$$ $$x = 7$$ 7. **Final answer:** The solution to the system is $$\boxed{(7, 3)}$$