1. **State the problem:** Solve the system of equations using substitution method: $$-2x + 3y = 0$$ $$x + y = -5$$ 2. **Choose one equation to express one variable in terms of the other:** From the second equation, $$x + y = -5 \implies x = -5 - y$$ 3. **Substitute this expression for $x$ into the first equation:** $$-2(-5 - y) + 3y = 0$$ 4. **Simplify and solve for $y$:** $$10 + 2y + 3y = 0$$ $$10 + 5y = 0$$ $$5y = -10$$ $$y = \frac{-10}{5}$$ $$y = -2$$ 5. **Substitute $y = -2$ back into the expression for $x$:** $$x = -5 - (-2)$$ $$x = -5 + 2$$ $$x = -3$$ 6. **Solution:** The solution to the system is $$\boxed{(-3, -2)}$$ This corresponds to option C.