Subjects algebra

Substitution Values Ae29Cf

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1. **State the problem:** Find the value of each expression when $p=2$. 2. **Evaluate (a) $6p - 10$:** Substitute $p=2$: $$6 \times 2 - 10 = 12 - 10 = 2$$ 3. **Evaluate (b) $\frac{p + 5}{14}$:** Substitute $p=2$: $$\frac{2 + 5}{14} = \frac{7}{14}$$ Simplify: $$\frac{\cancel{7}}{\cancel{14}} = \frac{1}{2}$$ 4. **Evaluate (c) $p + 30$:** Substitute $p=2$: $$2 + 30 = 32$$ 5. **Evaluate (d) $\frac{4p + 1}{3}$:** Substitute $p=2$: $$\frac{4 \times 2 + 1}{3} = \frac{8 + 1}{3} = \frac{9}{3}$$ Simplify: $$\frac{\cancel{9}}{\cancel{3}} = 3$$ 6. **Evaluate (e) Divide $3a$ by 17:** Expression is $\frac{3a}{17}$. Since $a$ is not given, the value is $\frac{3a}{17}$. 7. **Evaluate (f) Thrice of $14y$:** Thrice means multiply by 3: $$3 \times 14y = 42y$$ 8. **Evaluate (g) Subtract $7p$ from 15:** Substitute $p=2$: $$15 - 7 \times 2 = 15 - 14 = 1$$ 9. **Evaluate (h) Half of $120w$:** Half means divide by 2: $$\frac{120w}{2} = 60w$$ **Final answers:** (a) 2 (b) $\frac{1}{2}$ (c) 32 (d) 3 (e) $\frac{3a}{17}$ (f) $42y$ (g) 1 (h) $60w$