1. The problem is to subtract a fraction from a whole number in each case. 2. The formula for subtracting a fraction from a whole number $a - \frac{b}{c}$ is to write the whole number as a fraction with the same denominator: $a = \frac{a \times c}{c}$, then subtract the numerators: $$\frac{a \times c}{c} - \frac{b}{c} = \frac{a \times c - b}{c}$$ 3. Simplify the fraction if possible. Now, let's solve each: 1) $5 - \frac{8}{12} = \frac{5 \times 12}{12} - \frac{8}{12} = \frac{60 - 8}{12} = \frac{52}{12} = \frac{13}{3}$ 2) $3 - \frac{11}{15} = \frac{3 \times 15}{15} - \frac{11}{15} = \frac{45 - 11}{15} = \frac{34}{15}$ 3) $2 - \frac{10}{16} = \frac{2 \times 16}{16} - \frac{10}{16} = \frac{32 - 10}{16} = \frac{22}{16} = \frac{11}{8}$ 4) $7 - \frac{4}{9} = \frac{7 \times 9}{9} - \frac{4}{9} = \frac{63 - 4}{9} = \frac{59}{9}$ 5) $8 - \frac{3}{7} = \frac{8 \times 7}{7} - \frac{3}{7} = \frac{56 - 3}{7} = \frac{53}{7}$ 6) $4 - \frac{2}{5} = \frac{4 \times 5}{5} - \frac{2}{5} = \frac{20 - 2}{5} = \frac{18}{5}$ 7) $7 - \frac{1}{3} = \frac{7 \times 3}{3} - \frac{1}{3} = \frac{21 - 1}{3} = \frac{20}{3}$ 8) $9 - \frac{6}{7} = \frac{9 \times 7}{7} - \frac{6}{7} = \frac{63 - 6}{7} = \frac{57}{7}$ 9) $3 - \frac{9}{14} = \frac{3 \times 14}{14} - \frac{9}{14} = \frac{42 - 9}{14} = \frac{33}{14}$ 10) $5 - \frac{17}{20} = \frac{5 \times 20}{20} - \frac{17}{20} = \frac{100 - 17}{20} = \frac{83}{20}$ 11) $9 - \frac{4}{6} = \frac{9 \times 6}{6} - \frac{4}{6} = \frac{54 - 4}{6} = \frac{50}{6} = \frac{25}{3}$ 12) $2 - \frac{8}{13} = \frac{2 \times 13}{13} - \frac{8}{13} = \frac{26 - 8}{13} = \frac{18}{13}$ 13) $4 - \frac{7}{11} = \frac{4 \times 11}{11} - \frac{7}{11} = \frac{44 - 7}{11} = \frac{37}{11}$ 14) $6 - \frac{1}{2} = \frac{6 \times 2}{2} - \frac{1}{2} = \frac{12 - 1}{2} = \frac{11}{2}$ Each answer is a simplified improper fraction representing the result of subtracting the fraction from the whole number.