1. The problem asks to find the sum of the integers from 1 to 10. 2. We use the formula for the sum of the first $n$ natural numbers: $$S = \frac{n(n+1)}{2}$$ where $n=10$. 3. Substitute $n=10$ into the formula: $$S = \frac{10(10+1)}{2} = \frac{10 \times 11}{2}$$. 4. Simplify the multiplication: $$S = \frac{110}{2}$$. 5. Simplify the fraction by canceling common factors: $$S = \frac{\cancel{110}}{\cancel{2}} = 55$$. 6. Therefore, the sum of the integers from 1 to 10 is 55.