1. The problem asks to find the sum of the integers from 1 to 12. 2. We use the formula for the sum of the first $n$ natural numbers: $$S = \frac{n(n+1)}{2}$$ where $n=12$. 3. Substitute $n=12$ into the formula: $$S = \frac{12 \times (12+1)}{2} = \frac{12 \times 13}{2}$$. 4. Calculate the numerator: $12 \times 13 = 156$. 5. Divide by 2: $\frac{156}{2} = 78$. 6. Therefore, the sum of the integers from 1 to 12 is $78$.