1. The problem asks for the sum of the items from 1 to 12. 2. We use the formula for the sum of an arithmetic series: $$S_n = \frac{n}{2}(a_1 + a_n)$$ where $n$ is the number of terms, $a_1$ is the first term, and $a_n$ is the last term. 3. Here, $n = 12$, $a_1 = 1$, and $a_n = 12$. 4. Substitute the values into the formula: $$S_{12} = \frac{12}{2}(1 + 12)$$ 5. Simplify inside the parentheses: $$S_{12} = 6 \times 13$$ 6. Multiply to find the sum: $$S_{12} = 78$$ 7. Therefore, the sum of the items from 1 to 12 is 78.