1. The problem is to find the sum of all integers from 236 to 300 inclusive. 2. We use the formula for the sum of an arithmetic series: $$S_n = \frac{n}{2}(a_1 + a_n)$$ where $n$ is the number of terms, $a_1$ is the first term, and $a_n$ is the last term. 3. Calculate the number of terms: $$n = 300 - 236 + 1 = 65$$ 4. Substitute values into the formula: $$S_{65} = \frac{65}{2}(236 + 300)$$ 5. Simplify inside the parentheses: $$236 + 300 = 536$$ 6. Multiply: $$S_{65} = \frac{65}{2} \times 536$$ 7. Simplify the fraction by canceling common factors: $$\frac{65}{2} \times 536 = 65 \times \frac{536}{2} = 65 \times 268$$ 8. Calculate the product: $$65 \times 268 = 17420$$ 9. Therefore, the sum of integers from 236 to 300 is $$\boxed{17420}$$.