Subjects algebra

Sum Fractions 5B6A63

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1. The problem is to find the sum of the series $$\frac{1}{5} + \frac{2}{5} + \frac{3}{5} + \cdots + \frac{100}{5}$$. 2. We can factor out the common denominator 5 from each term: $$\frac{1}{5} + \frac{2}{5} + \frac{3}{5} + \cdots + \frac{100}{5} = \frac{1+2+3+\cdots+100}{5}$$. 3. The numerator is the sum of the first 100 natural numbers. The formula for the sum of the first $n$ natural numbers is: $$\sum_{k=1}^n k = \frac{n(n+1)}{2}$$. 4. Applying this formula for $n=100$: $$\sum_{k=1}^{100} k = \frac{100 \times 101}{2} = 50 \times 101 = 5050$$. 5. Substitute back into the expression: $$\frac{5050}{5} = 1010$$. 6. Therefore, the sum of the series is $1010$.