1. The problem is to evaluate the sum $$\sum_{i=1}^n 1^i$$.
2. Notice that for any integer $i$, $1^i = 1$ because any number to the power of $i$ is itself, and $1$ raised to any power is always $1$.
3. Therefore, the sum simplifies to adding $1$ exactly $n$ times.
4. So, $$\sum_{i=1}^n 1^i = \sum_{i=1}^n 1 = n$$.
5. The final answer is $$n$$.
Sum Of Ones
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