1. The problem is to understand the set $\mathrm{imf} = \left\{ \frac{m+n}{mn} \mid m,n \in \mathbb{N} \right\}$.
2. This set consists of all numbers that can be expressed as the sum of two natural numbers $m$ and $n$ divided by their product.
3. The formula is given by:
$$\frac{m+n}{mn}$$
where $m,n$ are natural numbers (positive integers).
4. Important rules:
- $m,n \in \mathbb{N}$ means $m,n$ are positive integers.
- The denominator $mn$ is never zero since $m,n$ are natural numbers.
5. Let's simplify the expression:
$$\frac{m+n}{mn} = \frac{m}{mn} + \frac{n}{mn} = \frac{1}{n} + \frac{1}{m}$$
6. So every element in the set can be written as the sum of the reciprocals of two natural numbers.
7. For example, if $m=1$ and $n=2$, then:
$$\frac{1+2}{1 \times 2} = \frac{3}{2} = 1.5$$
8. If $m=2$ and $n=3$, then:
$$\frac{2+3}{2 \times 3} = \frac{5}{6} \approx 0.8333$$
9. Therefore, the set $\mathrm{imf}$ contains all numbers of the form $\frac{1}{m} + \frac{1}{n}$ where $m,n$ are natural numbers.
Final answer:
$$\mathrm{imf} = \left\{ \frac{1}{m} + \frac{1}{n} \mid m,n \in \mathbb{N} \right\}$$
Sum Over Product F8Ae45
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