Subjects algebra

Sum Values 720Bbd

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1. **State the problem:** Find the sum of the values from 0 to 26 inclusive. 2. **Formula used:** The sum of the first $n$ natural numbers is given by the formula $$\text{Sum} = \frac{n(n+1)}{2}$$ where $n$ is the largest number in the sequence. 3. **Apply the formula:** Here, $n=26$. 4. **Calculate:** $$\text{Sum} = \frac{26 \times (26+1)}{2} = \frac{26 \times 27}{2}$$ 5. **Simplify:** $$= \frac{\cancel{26} \times 27}{\cancel{2} \times 1} = 13 \times 27$$ 6. **Multiply:** $$13 \times 27 = 351$$ 7. **Final answer:** The sum of the values from 0 to 26 is **351**.