1. **State the problem:** We are given the function $$q(v) = (v - 8)(v - 5)(v - 4)(v + 5)(v + 10)$$ and asked to find the sum of its zeros. 2. **Recall the rule:** The zeros of the function are the values of $$v$$ that make $$q(v) = 0$$. Since $$q(v)$$ is factored, the zeros are the roots of each factor. 3. **Find the zeros:** Set each factor equal to zero: $$v - 8 = 0 \Rightarrow v = 8$$ $$v - 5 = 0 \Rightarrow v = 5$$ $$v - 4 = 0 \Rightarrow v = 4$$ $$v + 5 = 0 \Rightarrow v = -5$$ $$v + 10 = 0 \Rightarrow v = -10$$ 4. **Sum the zeros:** Add all zeros together: $$8 + 5 + 4 + (-5) + (-10) = 8 + 5 + 4 - 5 - 10$$ 5. **Simplify the sum:** $$8 + 5 = 13$$ $$13 + 4 = 17$$ $$17 - 5 = 12$$ $$12 - 10 = 2$$ **Final answer:** The sum of the zeros of the function $$q(v)$$ is $$2$$.