1. **State the problem:** Two angles are supplementary, meaning their measures add up to 180 degrees. One angle is twelve degrees more than twice the other angle.
2. **Define variables:** Let the measure of the first angle be $x$ degrees.
3. **Express the second angle:** The second angle is twelve degrees more than twice the first angle, so it is $2x + 12$ degrees.
4. **Write the equation for supplementary angles:** Since the angles are supplementary, their sum is 180 degrees:
$$x + (2x + 12) = 180$$
5. **Simplify the equation:**
$$3x + 12 = 180$$
6. **Solve for $x$:**
$$3x = 180 - 12$$
$$3x = 168$$
$$x = \frac{168}{3} = 56$$
7. **Find the second angle:**
$$2x + 12 = 2(56) + 12 = 112 + 12 = 124$$
8. **Answer:** The two angles measure $56$ degrees and $124$ degrees respectively.
Supplementary Angles 0A3A1B
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