1. **State the problem:** Anna Lee has 3 bags of sweets with quantities 145, 206, and 167. 2. **Find the total number of sweets:** $$145 + 206 + 167 = 518$$ 3. **She repackaged all sweets into equal heaps of 3 and 4 sweets each.** 4. **Let $x$ be the number of heaps of 3 sweets, and $y$ be the number of heaps of 4 sweets.** 5. **The total sweets equation is:** $$3x + 4y = 518$$ 6. **The total number of heaps is:** $$x + y = n$$ 7. **From the problem, the total number of heaps is:** $$n = \frac{518}{3 + 4} = \frac{518}{7} = 74$$ 8. **So,** $$x + y = 74$$ 9. **Solve the system:** From $x + y = 74$, we get $$y = 74 - x$$ Substitute into the sweets equation: $$3x + 4(74 - x) = 518$$ $$3x + 296 - 4x = 518$$ $$-x + 296 = 518$$ $$-x = 518 - 296$$ $$-x = 222$$ $$x = -222$$ 10. **Since $x$ cannot be negative, check the problem statement again.** The problem states heaps of 3 and 4 sweets, and total heaps are 74. The equation $x 3 + x 4 = 518$ is ambiguous; it likely means $3x + 4y = 518$ with $x + y = 74$. Rearranging: $$3x + 4(74 - x) = 518$$ $$3x + 296 - 4x = 518$$ $$-x = 518 - 296$$ $$-x = 222$$ $$x = -222$$ This is impossible, so the problem likely means the heaps are formed separately, not combined. 11. **If sweets are repackaged in heaps of 3 and separately in heaps of 4, then:** - Number of heaps of 3 sweets: $$\frac{518}{3} = 172.666...$$ (not an integer) - Number of heaps of 4 sweets: $$\frac{518}{4} = 129.5$$ (not an integer) 12. **Alternatively, if the total sweets are divided into heaps of size 7 (3+4), then:** $$\frac{518}{7} = 74$$ heaps total. 13. **The number of sweets used to form heaps of 3 is:** $$74 \times 3 = 222$$ **Final answer:** $$\boxed{222}$$ sweets were used to form heaps of 3.