1. **Problem:** Determine whether the system of equations is consistent or inconsistent, independent or dependent. Given system: $$\begin{cases}-3x + y = -4 \\ -4x - y = -10\end{cases}$$ 2. **Step 1: Add the two equations to eliminate $y$.** $$(-3x + y) + (-4x - y) = -4 + (-10)$$ $$-3x - 4x + y - y = -14$$ $$-7x = -14$$ 3. **Step 2: Solve for $x$.** $$x = \frac{-14}{-7} = 2$$ 4. **Step 3: Substitute $x=2$ into the first equation to find $y$.** $$-3(2) + y = -4$$ $$-6 + y = -4$$ $$y = -4 + 6 = 2$$ 5. **Step 4: Check the solution in the second equation.** $$-4(2) - 2 = -8 - 2 = -10$$ True, so the system has one unique solution $(2,2)$. 6. **Conclusion:** The system is **consistent** (has at least one solution) and **independent** (exactly one solution). Final answer: **Consistent and independent**.