1. **State the problem:** Solve the system by substitution: $$y = 6x - 11$$ $$-2x - 3y = -7$$ 2. **Use substitution:** Since $y$ is already expressed in terms of $x$ in the first equation, substitute $y = 6x - 11$ into the second equation: $$-2x - 3(6x - 11) = -7$$ 3. **Simplify the equation:** $$-2x - 18x + 33 = -7$$ 4. **Combine like terms:** $$-20x + 33 = -7$$ 5. **Isolate $x$:** $$-20x = -7 - 33$$ $$-20x = -40$$ 6. **Divide both sides by $-20$:** $$x = \frac{\cancel{-40}}{\cancel{-20}} = 2$$ 7. **Find $y$ by substituting $x=2$ back into $y=6x-11$:** $$y = 6(2) - 11 = 12 - 11 = 1$$ **Final answer:** $$(x, y) = (2, 1)$$