Subjects algebra

Systems Substitution

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1. **State the problem:** Solve each system of equations using substitution. Identify which three systems have the solution $(4,16)$ and unscramble their letters to find a secret code. 2. **Recall substitution method:** Solve one equation for one variable, then substitute into the other equation. --- ### System T: \begin{cases} 7x + y = 12 \\ y = 4x - 21 \end{cases} Substitute $y$ from second into first: $$7x + (4x - 21) = 12$$ $$11x - 21 = 12$$ $$11x = 33$$ $$x = 3$$ Then $y = 4(3) - 21 = 12 - 21 = -9$ Solution: $(3, -9)$ ### System E: \begin{cases} 2x + 3y = 18 \\ y = -6x - 2 \end{cases} Substitute $y$: $$2x + 3(-6x - 2) = 18$$ $$2x - 18x - 6 = 18$$ $$-16x = 24$$ $$x = -\frac{24}{16} = -\frac{3}{2}$$ Then $y = -6(-\frac{3}{2}) - 2 = 9 - 2 = 7$ Solution: $(-\frac{3}{2}, 7)$ ### System U: \begin{cases} -3x + \frac{1}{4}y = -8 \\ 8x - y = 16 \end{cases} From second: $y = 8x - 16$ Substitute into first: $$-3x + \frac{1}{4}(8x - 16) = -8$$ $$-3x + 2x - 4 = -8$$ $$-x - 4 = -8$$ $$-x = -4$$ $$x = 4$$ Then $y = 8(4) - 16 = 32 - 16 = 16$ Solution: $(4,16)$ ### System R: \begin{cases} 11x + 9y = -20 \\ x = -5y - 6 \end{cases} Substitute $x$: $$11(-5y - 6) + 9y = -20$$ $$-55y - 66 + 9y = -20$$ $$-46y - 66 = -20$$ $$-46y = 46$$ $$y = -1$$ Then $x = -5(-1) - 6 = 5 - 6 = -1$ Solution: $(-1, -1)$ ### System B: \begin{cases} -2x + y = 8 \\ \frac{1}{2}x + 3y = 50 \end{cases} From first: $y = 2x + 8$ Substitute into second: $$\frac{1}{2}x + 3(2x + 8) = 50$$ $$\frac{1}{2}x + 6x + 24 = 50$$ $$6.5x = 26$$ $$x = 4$$ Then $y = 2(4) + 8 = 8 + 8 = 16$ Solution: $(4,16)$ ### System P: \begin{cases} 5x - 3y = -4 \\ y = \frac{5}{3}x + 6 \end{cases} Substitute $y$: $$5x - 3\left(\frac{5}{3}x + 6\right) = -4$$ $$5x - 5x - 18 = -4$$ $$-18 = -4$$ No solution (contradiction) --- ### Word Problem S (Piggy bank): \begin{cases} x + y = 20 \\ 0.10x + 0.25y = 4.40 \end{cases} From first: $y = 20 - x$ Substitute: $$0.10x + 0.25(20 - x) = 4.40$$ $$0.10x + 5 - 0.25x = 4.40$$ $$-0.15x = -0.60$$ $$x = 4$$ Then $y = 20 - 4 = 16$ Number of dimes: 4, quarters: 16 ### Word Problem A (Package): \begin{cases} x + y = 14 \\ x + 0.5y = 9 \end{cases} From first: $y = 14 - x$ Substitute: $$x + 0.5(14 - x) = 9$$ $$x + 7 - 0.5x = 9$$ $$0.5x = 2$$ $$x = 4$$ Then $y = 14 - 4 = 10$ Number of magazines: 4, chips: 10 --- ### Secret code: Systems with solution $(4,16)$ are U, B, and S. Unscramble letters: **SUB** **Final answers:** - Solutions for each system as above. - Secret code: **SUB**