1. **Problem Statement:** We are asked to complete the table of values for the function $$y = 2x^2 - 7x - 3$$ for $$x = -2, -1, 0, 1, 2, 3, 4, 5$$. 2. **Formula:** The function is given by $$y = 2x^2 - 7x - 3$$. 3. **Calculate each y-value:** - For $$x = -2$$: $$y = 2(-2)^2 - 7(-2) - 3 = 2(4) + 14 - 3 = 8 + 14 - 3 = 19$$ - For $$x = -1$$: $$y = 2(-1)^2 - 7(-1) - 3 = 2(1) + 7 - 3 = 2 + 7 - 3 = 6$$ - For $$x = 0$$: $$y = 2(0)^2 - 7(0) - 3 = 0 - 0 - 3 = -3$$ - For $$x = 1$$: $$y = 2(1)^2 - 7(1) - 3 = 2 - 7 - 3 = -8$$ - For $$x = 2$$: $$y = 2(2)^2 - 7(2) - 3 = 2(4) - 14 - 3 = 8 - 14 - 3 = -9$$ - For $$x = 3$$: $$y = 2(3)^2 - 7(3) - 3 = 2(9) - 21 - 3 = 18 - 21 - 3 = -6$$ - For $$x = 4$$: $$y = 2(4)^2 - 7(4) - 3 = 2(16) - 28 - 3 = 32 - 28 - 3 = 1$$ - For $$x = 5$$: $$y = 2(5)^2 - 7(5) - 3 = 2(25) - 35 - 3 = 50 - 35 - 3 = 12$$ 4. **Completed table:** | x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | | y | 19 | 6 | -3| -8| -9| -6| 1 | 12| This completes the first question as per instructions.