1. The problem asks to create tables of values for each equation in question 6 part a. 2. To create a table of values, choose several values for the independent variable (usually $x$), then calculate the corresponding dependent variable ($y$) using the equation. 3. For example, for equation i) $y = 2x + 8$: - Choose $x$ values: $-2, 0, 2, 4$ - Calculate $y$ for each: $$y = 2(-2) + 8 = -4 + 8 = 4$$ $$y = 2(0) + 8 = 0 + 8 = 8$$ $$y = 2(2) + 8 = 4 + 8 = 12$$ $$y = 2(4) + 8 = 8 + 8 = 16$$ 4. The table for i) is: | $x$ | $-2$ | $0$ | $2$ | $4$ | |-----|------|-----|-----|-----| | $y$ | $4$ | $8$ | $12$| $16$| 5. Repeat this process for each equation: - ii) $y = 0.5x + 12$ - iii) $y = x^2 + 8$ - iv) $y = 2x$ - v) $x = 7$ (Here $x$ is constant, so $y$ can be any value) - vi) $x + y = 6$ (Rewrite as $y = 6 - x$) 6. For each, pick $x$ values (e.g., $-2, 0, 2, 4$), then calculate $y$ accordingly. This method creates tables of values to help graph each relation.