1. **State the problem:** We have two types of tablets, Vita A and Vita B.
- Vita A contains 30 mg iron and 20 mg vitamin C per tablet.
- Vita B contains 10 mg iron and 30 mg vitamin C per tablet.
The daily needs are:
- At most 180 mg iron (iron intake \(\leq 180\))
- At least 1500 mg vitamin C (vitamin C intake \(\geq 1500\))
We want to find the system of inequalities representing these constraints.
2. **Define variables:**
Let \(x\) = number of Vita A tablets
Let \(y\) = number of Vita B tablets
3. **Write inequalities for iron and vitamin C:**
- Iron intake: \(30x + 10y \leq 180\) (since at most 180 mg iron)
- Vitamin C intake: \(20x + 30y \geq 1500\) (since at least 1500 mg vitamin C)
4. **Non-negativity constraints:**
\(x \geq 0, y \geq 0\) because number of tablets cannot be negative.
5. **Check options:**
- Option a: \(30x + 10y \leq 1800; 20x + 30y \geq 1500; x,y \geq 0\)
- Iron inequality has 1800 instead of 180, so incorrect.
- Option b: \(30x + 10y \geq 1800; 20x + 30y \geq 1500\)
- Iron inequality reversed and wrong number, incorrect.
- Option c: \(10x + 30y \leq 1800; 30x + 20y \geq 1500\)
- Coefficients swapped, incorrect.
- Option d: \(30x + 10y \leq 1500; 20x + 30y \leq 1800\)
- Vitamin C inequality reversed and numbers swapped, incorrect.
- Option e: None of the given options is correct.
6. **Conclusion:** None of the options matches the correct system:
$$
\begin{cases}
30x + 10y \leq 180 \\
20x + 30y \geq 1500 \\
x \geq 0, y \geq 0
\end{cases}
$$
Therefore, the correct answer is option e.
**Final answer:** e. None of the given options is correct.
Tablet Inequalities 968C41
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