1. **Problem statement:** We have a tablet with a capacity of 256 gigabytes (GB). Each byte corresponds to one character, and each page contains 2000 characters. We want to find: a. How many pages of text the tablet can hold. b. How many 500-page books the tablet can hold. 2. **Important information and formulas:** - 1 gigabyte (GB) = $10^9$ bytes (using decimal system for storage). - Total bytes in tablet = $256 \times 10^9$ bytes. - Characters per page = 2000. - Bytes per character = 1 (since 1 byte = 1 character). 3. **Step a: Calculate total pages the tablet can hold.** Total bytes = $256 \times 10^9$ bytes. Since 1 page = 2000 characters = 2000 bytes, Number of pages = $\frac{256 \times 10^9}{2000}$. Simplify: $$\frac{256 \times 10^9}{2000} = 256 \times \frac{10^9}{2000} = 256 \times 5 \times 10^5 = 1.28 \times 10^8$$ pages. 4. **Step b: Calculate how many 500-page books the tablet can hold.** Number of 500-page books = $\frac{\text{total pages}}{500} = \frac{1.28 \times 10^8}{500}$. Simplify: $$\frac{1.28 \times 10^8}{500} = 1.28 \times 10^8 \times \frac{1}{500} = 1.28 \times 10^8 \times 0.002 = 2.56 \times 10^5$$ books. **Final answers:** - a. The tablet can hold $1.28 \times 10^8$ pages of text. - b. The tablet can hold $2.56 \times 10^5$ books of 500 pages each.