1. **State the problem:** We need to find the term number $n$ in an arithmetic progression (A.P.) where the first term $a_1=3$, the common difference $d=7$, and the $n$th term $a_n=50$. 2. **Formula used:** The $n$th term of an A.P. is given by: $$a_n = a_1 + (n-1)d$$ 3. **Substitute the known values:** $$50 = 3 + (n-1)7$$ 4. **Solve for $n$:** $$50 - 3 = (n-1)7$$ $$47 = 7(n-1)$$ $$\frac{47}{7} = n - 1$$ $$n = 1 + \frac{47}{7} = \frac{7}{7} + \frac{47}{7} = \frac{54}{7}$$ 5. **Interpretation:** Since $n$ must be a positive integer (term number), and $\frac{54}{7}$ is not an integer, this means 50 is not exactly a term in the sequence. If the question intends to find the closest term number, it would be approximately 7.71, but strictly speaking, 50 is not a term. **Final answer:** There is no integer term number $n$ such that $a_n=50$ in this A.P.