1. The problem asks us to find the term at position $y+1$ in the sequence defined by $T(n) = 3n + 2$. 2. The formula for the term at position $n$ is given as: $$T(n) = 3n + 2$$ 3. To find $T(y+1)$, substitute $n$ with $y+1$: $$T(y+1) = 3(y+1) + 2$$ 4. Simplify the expression by distributing the 3: $$T(y+1) = 3y + 3 + 2$$ 5. Combine like terms: $$T(y+1) = 3y + 5$$ 6. Therefore, the term at position $y+1$ in the sequence is: $$\boxed{3y + 5}$$