1. **State the problem:** We have three types of tickets: child ticket costing $c$, adult ticket costing $c+4$, and senior ticket costing $c+3$. 2. **Write expressions for each family's total cost:** - Amelia's family has 3 children and 2 adults. Total cost = $3c + 2(c+4)$ - Manuel's family has 2 children, 1 adult, and 2 seniors. Total cost = $2c + (c+4) + 2(c+3)$ 3. **Simplify Amelia's family total:** $$3c + 2(c+4) = 3c + 2c + 8 = 5c + 8$$ 4. **Simplify Manuel's family total:** $$2c + (c+4) + 2(c+3) = 2c + c + 4 + 2c + 6 = (2c + c + 2c) + (4 + 6) = 5c + 10$$ 5. **Compare the two totals:** Amelia's family pays $5c + 8$ and Manuel's family pays $5c + 10$. 6. **Conclusion:** Since $5c + 10 > 5c + 8$ for any $c$, Manuel's family pays more. **Final answer:** Manuel's family pays more for the tickets.