1. **State the problem:** Jordan has 80 tickets. He wants to buy a bag of popcorn that costs 24 tickets and use the remaining tickets to play games. Each game requires 4 tickets. We need to find the greatest number of games Jordan can play, represented by $x$. 2. **Write the inequality:** The total tickets used for games plus the popcorn tickets must be less than or equal to 80 tickets. $$4x + 24 \leq 80$$ 3. **Solve the inequality:** Subtract 24 from both sides: $$4x + 24 - 24 \leq 80 - 24$$ $$4x \leq 56$$ Divide both sides by 4: $$\frac{\cancel{4}x}{\cancel{4}} \leq \frac{56}{4}$$ $$x \leq 14$$ 4. **Interpret the result:** Jordan can play at most 14 games because he cannot play a fraction of a game and must not exceed the ticket limit. **Final answer:** Jordan can play up to **14 games**.