1. **State the problem:** Dakola purchased tickets costing 35.50 each plus a 7 handling charge, spending less than 150 in total. We need to find the greatest number of tickets she could buy.
2. **Write the inequality:** Let $x$ be the number of tickets. The total cost is $7 + 35.50x$. Since she spent less than 150, the inequality is:
$$7 + 35.50x < 150$$
3. **Solve the inequality:** Subtract 7 from both sides:
$$\cancel{7} + 35.50x - \cancel{7} < 150 - 7$$
$$35.50x < 143$$
4. Divide both sides by 35.50:
$$\frac{35.50x}{35.50} < \frac{143}{35.50}$$
$$x < 4.028169014$$
5. Since $x$ represents the number of tickets, it must be a whole number less than 4.028, so the greatest integer $x$ is 4.
**Final answer:** Dakola can purchase at most **4 tickets**.
Ticket Inequality 68C9A7
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