1. **State the problem:** We have a total of 380 tickets sold for a school play. Adult tickets cost 12 each and student tickets cost 8 each. The total revenue from ticket sales is 3600. We need to find how many adult and student tickets were sold. 2. **Define variables:** Let $x$ be the number of adult tickets sold. Let $y$ be the number of student tickets sold. 3. **Write the system of equations:** Since the total tickets sold is 380: $$x + y = 380$$ Since the total revenue is 3600: $$12x + 8y = 3600$$ 4. **Solve the system:** From the first equation, express $y$ in terms of $x$: $$y = 380 - x$$ Substitute into the second equation: $$12x + 8(380 - x) = 3600$$ Distribute 8: $$12x + 3040 - 8x = 3600$$ Combine like terms: $$4x + 3040 = 3600$$ Subtract 3040 from both sides: $$4x = 3600 - 3040$$ $$4x = 560$$ Divide both sides by 4: $$\cancel{4}x = \cancel{4}140$$ $$x = 140$$ 5. **Find $y$:** $$y = 380 - 140 = 240$$ 6. **Answer:** The number of adult tickets sold is 140 and the number of student tickets sold is 240.