Subjects algebra

Tiles Pattern 66Bbe2

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1. The problem asks to find the number of tiles in the 8th pattern of a sequence where the number of tiles in the $n^{th}$ pattern is given by the formula: $$\text{Tiles} = 4n + 1$$ 2. This formula means for any pattern number $n$, multiply $n$ by 4 and then add 1 to get the total tiles. 3. To find the number of tiles in the 8th pattern, substitute $n = 8$ into the formula: $$\text{Tiles} = 4 \times 8 + 1$$ 4. Calculate the multiplication first: $$4 \times 8 = 32$$ 5. Then add 1: $$32 + 1 = 33$$ 6. Therefore, the 8th pattern has **33 tiles**.