1. The problem asks to find the number of tiles in the 8th pattern of a sequence where the number of tiles in the $n^{th}$ pattern is given by the formula:
$$\text{Tiles} = 4n + 1$$
2. This formula means for any pattern number $n$, multiply $n$ by 4 and then add 1 to get the total tiles.
3. To find the number of tiles in the 8th pattern, substitute $n = 8$ into the formula:
$$\text{Tiles} = 4 \times 8 + 1$$
4. Calculate the multiplication first:
$$4 \times 8 = 32$$
5. Then add 1:
$$32 + 1 = 33$$
6. Therefore, the 8th pattern has **33 tiles**.
Tiles Pattern 66Bbe2
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.