1. **State the problem:** You travel to a destination at 6 mph and return home at 4 mph. We need to find the distance traveled one way. 2. **Define variables:** Let $d$ be the one-way distance. 3. **Use the formula for time:** Time = Distance / Speed. 4. **Calculate time for each leg:** - Time going: $t_1 = \frac{d}{6}$ - Time returning: $t_2 = \frac{d}{4}$ 5. **Total time:** $T = t_1 + t_2 = \frac{d}{6} + \frac{d}{4}$ 6. **Combine fractions:** $$T = \frac{2d}{12} + \frac{3d}{12} = \frac{5d}{12}$$ 7. **Interpretation:** Without total time $T$, we cannot find a numeric value for $d$. The problem as stated lacks total time or total travel time information. 8. **Conclusion:** The distance traveled one way is $d = \frac{12T}{5}$, where $T$ is the total travel time. If you provide total travel time, we can calculate $d$ exactly.