1. The problem is to illustrate the trend line given by the equation $$y = -\frac{4}{5}x + 94$$. 2. This is a linear equation in slope-intercept form $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept. 3. Here, the slope $$m = -\frac{4}{5}$$ means the line decreases by 4 units vertically for every 5 units it moves horizontally to the right. 4. The y-intercept $$b = 94$$ means the line crosses the y-axis at the point $$(0, 94)$$. 5. To plot the line, start at $$(0, 94)$$ on the y-axis. 6. From there, move 5 units to the right (x increases by 5) and 4 units down (y decreases by 4) to get the next point at $$(5, 90)$$. 7. Connect these points with a straight line extending in both directions. 8. The equation and points confirm the trend line's negative slope and intercept. Final answer: The trend line is $$y = -\frac{4}{5}x + 94$$ with slope $$-\frac{4}{5}$$ and y-intercept 94.