1. **State the problem:** We need to find the equation of the trend line passing through the two yellow points on the scatter plot, which are approximately at coordinates $(40, 10)$ and $(80, 70)$. The equation should be in slope-intercept form $y = mx + b$. 2. **Formula for slope:** The slope $m$ of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Calculate the slope:** Using the points $(40, 10)$ and $(80, 70)$: $$m = \frac{70 - 10}{80 - 40} = \frac{60}{40}$$ 4. **Simplify the slope:** $$m = \frac{\cancel{60}^{3 \times 20}}{\cancel{40}^{2 \times 20}} = \frac{3}{2}$$ 5. **Use point-slope form to find $b$:** The slope-intercept form is $y = mx + b$. Substitute $m = \frac{3}{2}$ and one point, say $(40, 10)$: $$10 = \frac{3}{2} \times 40 + b$$ 6. **Calculate $b$:** $$10 = 60 + b$$ $$b = 10 - 60 = -50$$ 7. **Write the final equation:** $$y = \frac{3}{2}x - 50$$ This is the equation of the trend line in slope-intercept form.