1. **State the problem:** We need to find the equation of the trend line (line of best fit) passing through the two given points (4, 7) and (6, 0). 2. **Formula used:** The slope-intercept form of a line is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 7}{6 - 4} = \frac{-7}{2} = -\frac{7}{2}$$ 4. **Use point-slope form to find $b$:** Using point $(4,7)$, $$7 = -\frac{7}{2} \times 4 + b$$ $$7 = -14 + b$$ Add 14 to both sides: $$7 + 14 = b$$ $$b = 21$$ 5. **Write the equation:** $$y = -\frac{7}{2}x + 21$$ 6. **Explanation:** The slope is negative, indicating the line slopes downward. The y-intercept is 21, meaning the line crosses the y-axis at 21. **Final answer:** $$y = -\frac{7}{2}x + 21$$