1. **State the problem:** We need to find the equation of the trend line passing through the two yellow points on the scatter plot, which are approximately at coordinates $(1,1)$ and $(6,8)$. The equation should be in slope-intercept form $y=mx+b$. 2. **Formula and rules:** The slope $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m=\frac{y_2 - y_1}{x_2 - x_1}$$ The slope-intercept form is: $$y=mx+b$$ where $b$ is the y-intercept (value of $y$ when $x=0$). 3. **Calculate the slope:** Using points $(1,1)$ and $(6,8)$: $$m=\frac{8 - 1}{6 - 1}=\frac{7}{5}$$ 4. **Find the y-intercept $b$:** Substitute $m=\frac{7}{5}$ and point $(1,1)$ into $y=mx+b$: $$1=\frac{7}{5} \times 1 + b$$ $$1=\frac{7}{5} + b$$ Subtract $\frac{7}{5}$ from both sides: $$b=1 - \frac{7}{5} = \frac{5}{5} - \frac{7}{5} = -\frac{2}{5}$$ 5. **Write the final equation:** $$y=\frac{7}{5}x - \frac{2}{5}$$ This is the equation of the trend line in slope-intercept form.