Subjects algebra

Triangle Angles 77E1D8

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1. **State the problem:** We are given three angles of a triangle: $3h$, $h+10$, and $2h-40$. We need to find the smallest angle and compare it to 35. 2. **Recall the triangle angle sum rule:** The sum of the angles in any triangle is always 180 degrees. 3. **Set up the equation:** $$3h + (h + 10) + (2h - 40) = 180$$ 4. **Simplify the equation:** $$3h + h + 10 + 2h - 40 = 180$$ $$6h - 30 = 180$$ 5. **Solve for $h$:** Add 30 to both sides: $$6h - 30 + 30 = 180 + 30$$ $$6h = 210$$ Divide both sides by 6: $$\cancel{6}h = \frac{210}{\cancel{6}}$$ $$h = 35$$ 6. **Find each angle:** - $3h = 3 \times 35 = 105$ - $h + 10 = 35 + 10 = 45$ - $2h - 40 = 2 \times 35 - 40 = 70 - 40 = 30$ 7. **Identify the smallest angle:** The smallest angle is $30$ degrees. 8. **Compare to 35:** The smallest angle (30) is less than 35. **Final answer:** The smallest angle measures 30 degrees, which is less than 35.