1. **Stating the problem:**
We have a triangle with two equal sides each measuring $x+1$ meters and a base measuring $2x-1$ meters. The perimeter of the triangle is 17 meters.
2. **Setting up the equation:**
The perimeter $P$ of a triangle is the sum of all its sides. Here:
$$P = (x+1) + (x+1) + (2x-1)$$
Given $P = 17$, we write:
$$ (x+1) + (x+1) + (2x-1) = 17 $$
3. **Simplifying the equation:**
Combine like terms:
$$ x + 1 + x + 1 + 2x - 1 = 17 $$
$$ (x + x + 2x) + (1 + 1 - 1) = 17 $$
$$ 4x + 1 = 17 $$
4. **Solving for $x$:**
Subtract 1 from both sides:
$$ 4x + \cancel{1} - \cancel{1} = 17 - 1 $$
$$ 4x = 16 $$
Divide both sides by 4:
$$ \frac{4x}{\cancel{4}} = \frac{16}{\cancel{4}} $$
$$ x = 4 $$
5. **Answer:**
The value of $x$ is 4.
This means the two equal sides are each $4 + 1 = 5$ meters, and the base is $2(4) - 1 = 7$ meters, which sums to $5 + 5 + 7 = 17$ meters, confirming the solution.
Triangle Perimeter 66238C
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