1. **Problem statement:** You travel a base distance of 500 km for a round trip (aller-retour), but each additional friend you invite (up to 5 people including you) adds 10 km to the trip.
2. **Given data:**
- Base distance: 500 km
- Additional distance per friend: 10 km
- Fuel consumption: 15 L/100 km
- Fuel cost: 2 per liter
- Number of people including you: $n$, where $1 \leq n \leq 5$
3. **Goal:** Find the function $f(n)$ that gives the cost per person for the gas.
4. **Step 1: Calculate total distance for $n$ people.**
- Additional distance added: $(n-1) \times 10$ km
- Total one-way distance: $500 + 10(n-1)$ km
- Since the trip is round trip, total distance is:
$$D(n) = 2 \times \bigl(500 + 10(n-1)\bigr) = 2 \times (500 + 10n - 10) = 2 \times (490 + 10n) = 980 + 20n$$
5. **Step 2: Calculate total fuel consumption.**
- Fuel consumption rate: 15 L per 100 km
- Total fuel used:
$$F(n) = \frac{15}{100} \times D(n) = 0.15 \times (980 + 20n) = 147 + 3n$$ liters
6. **Step 3: Calculate total fuel cost.**
- Cost per liter: 2
- Total cost:
$$C(n) = 2 \times F(n) = 2 \times (147 + 3n) = 294 + 6n$$
7. **Step 4: Calculate cost per person.**
- Number of people: $n$
- Cost per person:
$$f(n) = \frac{C(n)}{n} = \frac{294 + 6n}{n}$$
8. **Step 5: Simplify the cost per person function.**
$$f(n) = \frac{294}{n} + 6$$
**Final answer:**
$$\boxed{f(n) = \frac{294}{n} + 6 \quad \text{for} \quad 1 \leq n \leq 5}$$
This function gives the gas cost per person depending on the number of people $n$ sharing the cost.
Trip Cost 0C5855
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