1. **State the problem:** We are given the tuition in 2001 as $4448$ and the percentage increase from 2001 to 2009 as $77.3\%$. We need to find the increase amount and the tuition for the 2009-2010 school year. 2. **Formula used:** The increase in tuition is calculated by multiplying the original tuition by the percentage increase (expressed as a decimal): $$\text{Increase} = \text{Original Tuition} \times \frac{\text{Percentage Increase}}{100}$$ The tuition for 2009-2010 is then: $$\text{Tuition}_{2009} = \text{Original Tuition} + \text{Increase}$$ 3. **Calculate the increase:** $$\text{Increase} = 4448 \times \frac{77.3}{100} = 4448 \times 0.773$$ 4. **Intermediate multiplication:** $$\text{Increase} = 4448 \times 0.773 = 3436.304$$ 5. **Calculate the tuition for 2009-2010:** $$\text{Tuition}_{2009} = 4448 + 3436.304$$ 6. **Intermediate addition:** $$\text{Tuition}_{2009} = 4448 + 3436.304 = 7884.304$$ 7. **Round to nearest cent:** Increase: $3436.30$ Tuition for 2009-2010: $7884.30$ **Final answers:** - Increase from 2001 to 2009: $3436.30$ - Tuition for 2009-2010 school year: $7884.30$