1. **Problem:** Find a number such that twice the sum of the number and three is 88. 2. **Step 1: Define the variable.** Let the number be $x$. 3. **Step 2: Write the equation.** Twice the sum of the number and three means $2(x + 3)$. 4. **Step 3: Set up the equation.** According to the problem, this equals 88: $$2(x + 3) = 88$$ 5. **Step 4: Solve the equation.** Distribute the 2: $$2x + 6 = 88$$ 6. **Step 5: Isolate $x$.** Subtract 6 from both sides: $$2x + \cancel{6} - \cancel{6} = 88 - 6$$ $$2x = 82$$ 7. **Step 6: Divide both sides by 2 to solve for $x$:** $$\frac{2x}{\cancel{2}} = \frac{82}{\cancel{2}}$$ $$x = 41$$ 8. **Answer:** The number is $41$. This completes the solution for the first exercise.