1. **Problem:** Anand's printer missed exponents and multiplication signs. The printed equation is $210 3100 = 3100$. We need to find the original equation. 2. **Understanding the problem:** The printed form removes exponents and multiplication signs. So $2^{10} \times 3^{100}$ would print as $210 3100$. 3. **Check options:** - A: $2^{10} \times 3^{100} = 3100$? Calculate $2^{10} = 1024$, $3^{100}$ is huge, so product is huge, not 3100. - B: $21^{0} \times 310^{0} = 3100$? $21^{0} = 1$, $310^{0} = 1$, product $=1$, not 3100. - C: $21^{0} \times 3100 = 3100$? $21^{0} = 1$, so product $=3100$, matches RHS. - D: $21^{0} + 3100 = 3100$? $21^{0} = 1$, sum $=3101$, not 3100. 4. **Answer:** Option C is correct. **Final answer:** C. $21^{0} \times 3100 = 3100$