1. **State the problem:** We are given that Hugo pays 4.50 for 6 hardcover books, all priced the same. We need to find the unit price of one book. 2. **Formula and explanation:** The unit price is found by dividing the total price by the number of books: $$\text{Unit price} = \frac{\text{Total price}}{\text{Number of books}}$$ 3. **Calculate unit price:** $$\text{Unit price} = \frac{4.50}{6}$$ Show division with cancellation: $$\frac{\cancel{4.50}}{\cancel{6}} = 0.75$$ 4. **Answer:** The unit price of each hardcover book is $0.75$. --- 1. **State the problem:** Sonia pays 1.50, John pays 6.00, and Keisha pays 3.75 for hardcover books at $0.75 each. Find how many books each bought. 2. **Formula:** Number of books = Total price ÷ Unit price 3. **Calculate for Sonia:** $$\frac{1.50}{0.75} = 2 \quad \Rightarrow \quad \frac{\cancel{1.50}}{\cancel{0.75}} = 2$$ 4. **Calculate for John:** $$\frac{6.00}{0.75} = 8 \quad \Rightarrow \quad \frac{\cancel{6.00}}{\cancel{0.75}} = 8$$ 5. **Calculate for Keisha:** $$\frac{3.75}{0.75} = 5 \quad \Rightarrow \quad \frac{\cancel{3.75}}{\cancel{0.75}} = 5$$ 6. **Answer:** Sonia bought 2 books, John bought 8 books, and Keisha bought 5 books. --- 1. **State the problem:** Kim buys 10 hardcover books at $0.75 each. Find how much she pays and explain the operation used. 2. **Formula:** Total price = Number of books × Unit price 3. **Calculate:** $$10 \times 0.75 = 7.50$$ 4. **Answer:** Kim pays $7.50. We used multiplication because we are finding the total cost for multiple items at the same unit price. --- 1. **State the problem:** Paperback books cost $0.25 less than hardcover books. How many more paperback books than hardcover books can be bought with $3.00? 2. **Calculate paperback price:** $$0.75 - 0.25 = 0.50$$ 3. **Calculate number of hardcover books for $3.00:** $$\frac{3.00}{0.75} = 4$$ 4. **Calculate number of paperback books for $3.00:** $$\frac{3.00}{0.50} = 6$$ 5. **Calculate difference:** $$6 - 4 = 2$$ 6. **Answer:** You can buy 2 more paperback books than hardcover books with $3.00.