1. **State the problem:** We have a blueprint where Fence A is represented as 1/5 feet in real life but measures 1 4/5 inches on the blueprint. We need to find the unit rate in inches per foot on the blueprint. 2. **Convert mixed numbers to improper fractions:** - Fence A length on blueprint: 1 4/5 inches = $$\frac{9}{5}$$ inches - Fence A real length: $$\frac{1}{5}$$ feet 3. **Find the unit rate (inches per foot):** The unit rate is the ratio of inches on the blueprint to feet in real life: $$\text{Unit rate} = \frac{\text{inches on blueprint}}{\text{feet real}} = \frac{\frac{9}{5}}{\frac{1}{5}}$$ 4. **Simplify the unit rate:** $$\frac{\frac{9}{5}}{\frac{1}{5}} = \frac{9}{5} \times \frac{5}{1} = 9$$ So, the unit rate is 9 inches per foot. 5. **Find the length of Fence B on the blueprint:** Fence B is 2 feet long in real life. Using the unit rate: $$\text{Length on blueprint} = 2 \text{ feet} \times 9 \frac{\text{inches}}{\text{foot}} = 18 \text{ inches}$$ **Final answers:** - Unit rate: 9 inches per foot - Fence B length on blueprint: 18 inches