1. The first line passes through points (0, -2) and (5, 7). Its slope is calculated as $$ m=\frac{7-(-2)}{5-0}=\frac{9}{5} $$ The equation of this solid line in slope-intercept form is: $$ y=\frac{9}{5}x - 2 $$ Since the shaded region is above this line, the unshaded region is below it, so the inequality is: $$ y \leq \frac{9}{5}x - 2 $$ 2. The second dashed line passes through (0, 6) and (6, 0). Calculate its slope: $$ m=\frac{0-6}{6-0}=-1 $$ Equation of the dashed line: $$ y = -x + 6 $$ The shaded region is below this line; therefore, the unshaded region is above it, so the inequality is: $$ y \geq -x + 6 $$ Final inequalities describing the unshaded region are: $$ y \leq \frac{9}{5}x - 2 $$ $$ y \geq -x + 6 $$