1. Let's start by stating the problem: We want to understand why at $x=0$, the value of $y$ is 20 and not 32. 2. Usually, the value of $y$ at a specific $x$ depends on the function or equation defining $y$ in terms of $x$. For example, if $y=f(x)$, then $y$ at $x=0$ is $f(0)$. 3. To explain why $y=20$ and not 32 at $x=0$, we need the exact function or equation for $y$. Without it, we can only explain the general principle: the value of $y$ at $x=0$ is the output of the function when $x$ is substituted by 0. 4. For example, if $y=20 + 12x$, then at $x=0$, $y=20 + 12\times0=20$. 5. If someone expected $y=32$ at $x=0$, they might have mistakenly substituted or assumed a different function. 6. In summary, the value of $y$ at $x=0$ depends entirely on the function's formula. To confirm why $y=20$ and not 32, check the function and substitute $x=0$ carefully. Final answer: $y=20$ at $x=0$ because that is the function's value when $x=0$, not 32.