1. The problem is to understand the given variables: $a=0$, $b=4$, $c=2$, $d=7$, $b_1=0$, and $b_2=4$. 2. Since no specific equation or context is provided, we can interpret these as constants or coefficients in an algebraic or physics problem. 3. If these represent coefficients of a quadratic equation $ax^2 + bx + c = 0$, then with $a=0$, the equation reduces to a linear equation $4x + 2 = 0$. 4. To solve $4x + 2 = 0$, subtract 2 from both sides: $4x = -2$. 5. Divide both sides by 4: $x = \frac{-2}{4} = -\frac{1}{2}$. 6. The values $d=7$, $b_1=0$, and $b_2=4$ are not used in this linear equation context without further information. 7. Therefore, the solution for $x$ given $a=0$, $b=4$, and $c=2$ in the quadratic form is $x = -\frac{1}{2}$.